File python-2.7.7-mhlib-linkcount.patch of Package python-doc

Index: Python-2.7.7/Lib/mhlib.py
===================================================================
--- Python-2.7.7.orig/Lib/mhlib.py	2014-05-31 20:58:39.000000000 +0200
+++ Python-2.7.7/Lib/mhlib.py	2014-07-24 16:08:26.049343760 +0200
@@ -156,11 +156,6 @@
         """Return the names of the subfolders in a given folder
         (prefixed with the given folder name)."""
         fullname = os.path.join(self.path, name)
-        # Get the link count so we can avoid listing folders
-        # that have no subfolders.
-        nlinks = os.stat(fullname).st_nlink
-        if nlinks <= 2:
-            return []
         subfolders = []
         subnames = os.listdir(fullname)
         for subname in subnames:
@@ -168,11 +163,6 @@
             if os.path.isdir(fullsubname):
                 name_subname = os.path.join(name, subname)
                 subfolders.append(name_subname)
-                # Stop looking for subfolders when
-                # we've seen them all
-                nlinks = nlinks - 1
-                if nlinks <= 2:
-                    break
         subfolders.sort()
         return subfolders
 
@@ -183,11 +173,6 @@
     def listallsubfolders(self, name):
         """Return the names of subfolders in a given folder, recursively."""
         fullname = os.path.join(self.path, name)
-        # Get the link count so we can avoid listing folders
-        # that have no subfolders.
-        nlinks = os.stat(fullname).st_nlink
-        if nlinks <= 2:
-            return []
         subfolders = []
         subnames = os.listdir(fullname)
         for subname in subnames:
@@ -200,11 +185,6 @@
                     subsubfolders = self.listallsubfolders(
                               name_subname)
                     subfolders = subfolders + subsubfolders
-                # Stop looking for subfolders when
-                # we've seen them all
-                nlinks = nlinks - 1
-                if nlinks <= 2:
-                    break
         subfolders.sort()
         return subfolders